Answer:
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Explanation:
The genotype of a color-blind man is X^cY and the genotype of the heterozygous carrier female is X^cX. A cross between X^cY and X^cX would produce a progeny in following ratio=
25% colorblind daughter: 25% colorblind son: 25% carrier daughters with normal vision: 25% normal son.
Therefore, the couple is likely to have 50% normal son and 50% affected son. Likewise, the couple is likely to have 50% normal daughters and 50% colorblind daughters.
Polypeptide chains undergo some modifications before they become fully functional. Some of these modifications include: proteolytic cleavage, lipidation and glycosylation. Proteolytic cleavage refers to the removal of some amino acids from a polypeptide chain by proteases in order for the protein to become active. An example of a substance that is modified through this process is insulin.
I am not sure if its going to be right or wrong but I would pick either C or A