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KIM [24]
4 years ago
13

Given: Base ∠BAC and ∠ACB are congruent.

Mathematics
2 answers:
Sergio039 [100]4 years ago
8 0

Refer to the image attached.

Given: \angle BAC and \angle ACB are congruent.

To Prove: \DeltaABC is an isosceles triangle.

Construction: Construct a perpendicular bisector from point B to Line segment AC.

Consider triangle ABD and BDC,

\angle BAD = \angle BCD (given)

\angle ADB = \angle BDC = 90^\circ

(By the definition of a perpendicular bisector)

AD=DC (By the definition of a perpendicular bisector)

Therefore, \Delta ABD \cong \Delta BDC by Angle Side Angle(ASA) Postulate.

Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent.(CPCTC)

BartSMP [9]4 years ago
6 0
Blank 1: *ASA Postulate*
Blank 2: *CPCTC*

Based on the info. your given and I drew (screenshot). Blank 1 is ASA Post. and Blank 2 is CPCTC because of ASA Post.

i am so sorry!
I meant to draw line segment AD is congruent to AC.... However Line segment AB is congruent to BC....

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LiRa [457]

Answer:

D. 7.8°

Step-by-step explanation:

There are many ways to work this problem. One is to subtract the angle of V from that of W:

∠V = arctan(2/-5) ≈ 158.20°

∠W = arctan(2/-8) ≈ 165.96°

Then ∠W -∠V = 165.96° -158.20° = 7.76° ≈ 7.8°

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Another is to divide W by V, since the quotient will have an angle that is the difference of their two angles.

(-8i +2j)/(-5i +2j) = (1/29)(44i +6j)

Then the angle of that is ...

arctan(6/44) ≈ 7.8°

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You can also divide the dot product by the product of the two magnitudes to find the cosine of the angle between the vectors.

(V•W)/(|V|·|W|) = 44/√(68·29) = cos(x)

x = arccos(0.990830168...) ≈ 7.8°

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A plot on graph paper will let you measure the angle with a protractor. You can obtain sufficient accuracy to choose between the offered answers.

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Your graphing calculator may have complex number functions that let you work directly with the angles of the vectors. (See second attachment. The calculator is in degrees mode.) Doing 2-dimensional vector calculations on a calculator may best be accomplished by treating them as complex numbers.

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4 years ago
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Akimi4 [234]

Answer:

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volume before reducing=

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volume of sphere when diameter reduced by 1/2=

V=4/3πr³

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<h2>volume before reducing is <u>8</u> times the volume after reducing</h2>

5 0
3 years ago
Find the lateral area of the cylinder.<br><br>Give your answer in the terms of pi.
Wewaii [24]
Hi there! 

The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. (two times pi times radius times height) Using this formula, we can plug in the values and solve for the lateral area.

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