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enot [183]
3 years ago
15

During the two hours of the morning rush from 8

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0
80 customers per hour
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Determine whether the ordered pair (6, 1) satisfies the equation y = 10 - 4x
Viktor [21]
Plug in the point
1 = 10 - 4(6)
1 = 10 - 24
1 = -14, false
Solution: B
4 0
3 years ago
For the polynomial function ƒ(x) = x4 − 12x3 + 46x2 − 60x + 25, find all local and global extrema.
rodikova [14]
\bf f(x)=x^4-12x^3+46x^2-60x+25\\\\
-------------------------------\\\\
\cfrac{df}{dx}=4x^3-36x^2+92x-60\implies 0=4x^3-36x^2+92x-60
\\\\\\
0=x^3-9x^2+23x-15\impliedby \textit{doing some synthetic division with 5}
\\\\\\
0=(x^2-4x+3)(x-5)\implies 0=(x-3)(x-1)(x-5)\\\\
-------------------------------\\\\
\begin{cases}
f(1)=0\leftarrow minimum&1,0\\
f(3)=16\leftarrow maximum&3,16\\
f(5)=0\leftarrow minimum&5,0
\end{cases}\impliedby \textit{3 extrema, locals and globals}
4 0
3 years ago
Exit
lukranit [14]
C is the answer to your question
4 0
3 years ago
Read 2 more answers
DUE IN 6 MINUTES!!
enyata [817]

Answer:

the answer is the first one

3 0
3 years ago
A laboratory scale is known to have a standard deviation of Ï = 0.001 gram in repeated weighings. Scale readings in repeated wei
erica [24]

Answer:

the confidence interval for the true weight of the specimen is;

4.1593 ≤ μ ≤ 4.1611

Step-by-step explanation:

We are given;

Standard deviation; σ = 0.001

Sample size; n = 8

Average weight; x¯ = 4.1602

We are given a 99% confidence interval and the z-value at this interval is 2.576

Formula for confidence interval is;

CI = x¯ ± (zσ/√n)

Plugging in the relevant values, we have;

CI = 4.1602 ± (2.576 × 0.001/√8)

CI = 4.1602 ± 0.000911

CI = (4.1602 - 0.000911), (4.1602 + 0.000911)

CI ≈ (4.1593, 4.1611)

Thus, the confidence interval for the true weight will be expressed as;

4.1593 ≤ μ ≤ 4.1611

Where μ represents the true weight

4 0
3 years ago
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