3 years ago

Please help me with the answer

Mathematics

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer is D

$\frac{4}{x+3}* \frac{x^2+6x+9}{16}= \frac{1}{(x+3)}* \frac{(x+3)^2}{4}= \frac{x+3}{4}$

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