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andreyandreev [35.5K]

3 years ago

8

Five family members are going to a play. A service charge of $2 is added to the cost of each ticket. The family is willing to pa

y $250 or less for the five tickets. What is the greatest amount the family is willing to pay for each ticket? PLEASEE HELPPP ME

2 answers:

katen-ka-za [31]3 years ago

7 0

250 ÷5 = 50

$50

Hope this helps!

aalyn [17]3 years ago

4 0

Five family members so 250 Divided by 5 is 50 so a maximum of $50

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Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

Suppose that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each

stich3 [128]

We have been given that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.

We will use sum of geometric sequence formula to solve our given problem.

$S_n=\frac{a\cdot(1-r^n)}{1-r}$ , where,

a = First term of sequence,

r = Common ratio,

n = Number of terms.

For our given problem $a=50$ , $r=50\%=\frac{50}{100}=0.5$ and $n=25$ .

$S_{25}=\frac{50\cdot(1-(0.5)^{25})}{1-0.5}$

$S_{25}=\frac{50\cdot(1-0.0000000298023224)}{0.5}$

$S_{25}=\frac{50\cdot(0.9999999701976776)}{0.5}$

$S_{25}=100\cdot(0.9999999701976776)$

$S_{25}=99.99999701976776\approx 100$

Therefore, the ball will travel 100 meters and option B is the correct choice.

4 0

3 years ago

Which of the following polynomials is in standard form?

Marianna [84]

Answer:

d

Step-by-step explanation:

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2 years ago

Write in simplest radical form: √208

Arte-miy333 [17]

$208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\Answer:\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a$

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4 years ago

Which expression is equivalent to V-80?<br> -455<br> O -4.5;<br> O 4.5;<br> O 415

steposvetlana [31]

Answer:

v-12

Step-by-step explanation:

1Nonly_n8thanfull

4 0

2 years ago

Read 2 more answers