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3 years ago

What is the order of rotational symmetry for a mombus? 0 1

Mathematics

1 answer:

Elan Coil [88]3 years ago

7 0

Answer: order 2

Step-by-step explanation:

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Point A is located at (5, 10) and point B is located at (20, 25).

Alla [95]

Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at a ratio of 7, thus 3:7,

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
A(5,10)\qquad B(20,25)\qquad
\qquad 3:7
\\\\\\
\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\
-------------------------------\\\\
{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\
-------------------------------$

$\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)
\\\\\\
C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10} \right)
\\\\\\
C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2} \right)$

8 0

3 years ago

Please answer this correctly

sesenic [268]

Answer:

Step-by-step explanation:

The sorted data set is ...

1 2 3 3 5 7 8 9

The median is the average of the middle two numbers: (3+5)/2 = 4.

Replacing one of the 3s with a 1 makes the data set be ...

1 1 2 3 5 7 8 9

The average of the middle two numbers is (3+5)/2 = 4.

The median increases by 4 - 4 = 0.

7 0

3 years ago

Please help i really really need help

pishuonlain [190]

Answer:

Step-by-step explanation:

The second one!!!

3 0

3 years ago

I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5

Gnesinka [82]

Given:
$f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}$

Using
$\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}$
we derive
$\frac{d}{dx}4xcos^{-1}(2x+4)$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}$

Similarly, using
$\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}$
we derive
$\frac{d}{dx}(-\sqrt{3-3x^2})$
$=\frac{3x}{\sqrt{3-3x^2}}$

Therefore, the derivative is
$f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})$
$=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}$

3 0

3 years ago

Read 2 more answers

1. What is the sum or difference?<br> 6x4 - 10x4

GalinKa [24]

Answer:

=6×4-10×4

=24-40

=-16

.......

6 0

2 years ago