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Luden [163]
2 years ago
6

Circle o has a circumference of 28.3 cm. What is the length of the radius r?

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
4 0
Circumference = 2Pi * r

28.3cm = 2pi * r ( Isolate r )
28.3cm / 2pi = r
R = 4.504

To verify work we can plug 4.504 back into the equations.

Circumference = 2pi*4.504 ~ 28.299 Which is true !
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A wedding ring is dropped from a tall building, the distance it has fallen in feet is given by 16t^2, where t is the time in sec
natka813 [3]

Answer:

64

Step-by-step explanation:

As given, the diatance at any point after t seconds is given by

s(t)=16t²

At t=2 seconds then

s(2)=16*2²=16*4=64

Since we're not given the units, it may be feet, inches, meters, kilometers, miles etc. Therefore, the diatance is equal to 64 units

7 0
2 years ago
Which of the following is equivalent to –(–5.25) ? 5 5.25 –5 –5.25<br>please answer fast​
Marina86 [1]

Answer:

The equivalent to -(-5.25) = 5.25

Step-by-step explanation:

Given

-(-5.25)

We need to determine the equivalent to -(-5.25)

some of the sign rules are:

+(+) = +      

−(−) = +

+(−) = -

−(+) = -

Thus,

-(-5.25)

Applying the rule: -a(-a) = a

=5.25

Therefore, the equivalent to -(-5.25) = 5.25

5 0
2 years ago
Read 2 more answers
Please help i really need it
masha68 [24]

Answer:

y = 108°

Step-by-step explanation:

Since AB and CD are parallel lines, then

3x - 12 and 2x + 16 are corresponding angles and congruent, thus

3x - 12 = 2x + 16 ( subtract 2x from both sides )

x - 12 = 16 ( add 12 to both sides )

x = 28

Thus

3x - 12 = 3(28) - 12 = 84 - 12 = 72°

y and 3x - 12 are adjacent angles and supplementary, thus

y = 180° - 72° = 108°

7 0
3 years ago
Read 2 more answers
Can you help me solve an infinite geometric sequence
zaharov [31]

A geometric series like

\displaystyle \sum_{n=1}^\infty \dfrac{1}{\alpha^n}

Converges if and only if |\alpha|>1. If this is the case, the sum equals

\displaystyle \sum_{n=1}^\infty \dfrac{1}{\alpha^n} = \dfrac{1}{\alpha-1}

So, in your case, you have convergence if and only if

|2+a|>1 \iff 2+a>1 \lor 2+a-1 \lor a

And if this is the case, the sum equals

\displaystyle \sum_{n=1}^\infty \dfrac{1}{(2+a)^n} = \dfrac{1}{2+a-1} = \dfrac{1}{a+1}

8 0
3 years ago
Anyone knows the answer
jarptica [38.1K]
It's C)

the graph is decrasing, so the variable rate is negative (-2/3)

the rest was quite easy, you just take a look at where the graph cuts the y-axis and determine the rest from the rate of going up or down (increase/decrease)
4 0
3 years ago
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