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Artyom0805 [142]
3 years ago
8

A square that has 28 cm long edges is centered on the x-axis in a region where there exists a uniform electric field given by =

(1.2 kN/C). What is the electric flux of this electric field through the surface of a square if the normal to the surface is in the +x direction?
Mathematics
1 answer:
Alja [10]3 years ago
3 0

Answer:

Step-by-step explanation:

  • From ΦE = ∫s E * dA
  • Given E= 1.2 kN/C = 1200N/C
  • L = 28cm = 0.28m
  • A = Area = (0.28)^2 = 0.0784m^2
  • electric flux = EA = 1200N/C x 0.0784m^2

= 94.08Nm2/C

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What are the values of x and y?
tresset_1 [31]

Step-by-step explanation:

y is easy.

it is the Hypotenuse (baseline) of the small right-angled triangle created by the height (8) of the main triangle, the segment 6 of the main Hypotenuse and y.

so, Pythagoras :

y² = 8² + 6² = 64 + 36 = 100

y = 10

x is a bit more complex.

I think the easiest way to get it is to know that the height of a right-angled triangle to the Hypotenuse is the square root of the product of both segments of the Hypotenuse.

so, if we call the segments of the Hypotenuse a and b with a = 6, we have

x = a + b = 6 + b

height (8) = sqrt(a×b) = sqrt(6b)

therefore,

6b = height² = 8² = 64

b = 64/6 = 32/3 = 10 2/3 = 10.66666666...

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round it to what is needed. e.g. 2 positions after the decimal point (hundredths) ? then it would be 10.67

6 0
3 years ago
1. Let the sample space represent all the values from 1 to 10. Let A = {1, 2, 8} and B = {2, 7}. What is the P(A ∩ B)?
AnnZ [28]

A \cap B denotes to all common elements in both A and B

  • Sample space=S={1,2,3,4,5,6,7,8,9,10}

So

  • A={1,2,8}
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2 is common

Hence

A $\cap$ B={2}

7 0
2 years ago
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Step-by-step explanation:

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3 years ago
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Ne4ueva [31]

Answer:

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x^2+x+2-y=0

x=-1<u>+</u>\sqrt{1^2-4(2-y)} /2

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