After the 10% discount on marked price (P), the selling price is ...
... P×(100% -10%) = 0.90P
After a markup off 35% on cost, the value is
... $70×(100% +35%) = 1.35×$70 = $94.50
The retailer wants these two values to be equal:
... 0.90P = $94.50
... P = $94.50/0.90 = $105.00 . . . . . divide by the coefficient of P
The marked price should be $105.00.
Answer:
They are both right angles and they both have a measure of 28°.
Step-by-step explanation:
angle A and angle B are both right angles (90°), and they both have a side measuring 28°. For the missing sides of both the measurement should be 62°.
Here you go let me know if you have questions
Answer:
About 609,000 Cowboy stadiums could fit inside of Mount Everest
Step-by-step explanation:
we have
The estimate volume of Mount Everest is at around 
The Dallas Cowboys Stadium has a volume of 
step 1
Convert ft³ to km³
we know that
1 km=3,280.84 ft
so

step 2
To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

Round to the nearest Thousands

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium