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umka2103 [35]
4 years ago
6

How many ways are there to select 12 countries in the United Nations to serve on a council if 3 are selected from a block of 45,

4 are selected from a block of 57, and the others are selected from the remaining 69 countries?
Mathematics
1 answer:
sattari [20]4 years ago
8 0

Answer: There are 2346953264 ways to do so.

Step-by-step explanation:

Since we have given that

Total number of selected countries = 12

Number of selected countries from a block of 45 = 3

Number of selected countries from a block of 57 = 4

So, remaining number of selected countries from a block of 69.

So, 12-(3+4)=12-7=5

Now, we need to find the number of ways, so we will use "Combination" to select that number of countries.

So, it becomes.

^{45}C_3\times ^{57}C_4\times ^{57}C_5\\\\=14190\times 395010\times 4187106\\\\=2346953264

Hence, there are 2346953264 ways to do so.

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A, B, C, E

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9. Aaron has a lemonade business. If he sells each glass of lemonade for $2.75, and he sold 11
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Exhibit 6-5 The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation o
hjlf

Answer:

46.18% of the items will weigh between 6.4 and 8.9 ounces.

Step-by-step explanation:

We are given that the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.

<em>Let X =  weight of items produced by a machine</em>

The z-score probability distribution for is given by;

                Z = \frac{  X -\mu}{\sigma}  ~ N(0,1)

where, \mu = mean weight = 8 ounces

            \sigma = standard deviation = 2 ounces

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, percentage of items that will weigh between 6.4 and 8.9 ounces is given by = P(6.4 < X < 8.9) = P(X < 8.9 ounces) - P(X \leq 6.4 ounces)

   P(X < 8.9) = P( \frac{  X -\mu}{\sigma} < \frac{  8.9-8}{2} ) = P(Z < 0.45) = 0.67364  {using z table}

   P(X \leq 70) = P( \frac{  X -\mu}{\sigma} \leq \frac{  6.4-8}{2} ) = P(Z \leq -0.80) = 1 - P(Z < 0.80)

                                                 = 1 - 0.78814 = 0.21186

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.45 and x = 0.80 in the z table which has an area of </em>0.67364<em> and </em>0.78814<em> respectively.</em>

Therefore, P(6.4 < X < 8.9) = 0.67364 - 0.21186 = 0.4618 or 46.18%

<em>Hence, 46.18% of the items will weigh between 6.4 and 8.9 ounces.</em>

8 0
4 years ago
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