450 ....................................................................................
We are given:
p = probability = 0.12<span>
n = total students = 39 </span>
x = left handers = 5<span>
u = mean = p* n = 4.68
σ = standard dev = √ ( n*p*(1-p)) = √ ( 39 * 0.12 * 0.88 ) =
2.03</span>
Calculating for the z score:
z = (x – u) / σ<span>
z = (5 – 4.68) / 2.03</span>
<span>z
= 0.1576 = 0.16
</span>
Using the standard tables for z, the p value is:
p value = 0.5636 = 56.36%
Hence there is a 56.36% chance.
<span> </span>
8 would be the coefficient :)
2 out of 50 are defective.
Divide 2 by 50: 2/50 = 0.04
Now multiply the total quantity by that:
2000 x 0.04 = 80
80 are likely to be defective.
Answer:
Multiply the first equation by five to yield, 15x + 5y = 45. Add this equation to the second equation from the given,
15x + 5y = 45
+ 3x - 5y = 15
The answer would be 18x = 60. The value of x is 10/3. Therefore, the answer to this item is letter A.
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Step-by-step explanation: