Since the first part says the value is five less then twice the square of a negative number we get the first equation as 2(-x)²-5. Then we have that -9x is equal to that previous equation. Therefore our new equation is 2(-x)²-5=-9x. We can move the nine over by adding it to both side to get 2(-x)²+9x-5=0. Then you can use any method of factoring (I prefer quadratic formula) to get your values for x. By doing so, you’ll get x=28 and x=-32.5. Since the problem said the number was negative in the first part, you know you can’t have the 28 as the answer so the right answer is -32.5.
Answer:
5 (3a+4)
Step-by-step explanation:
Answer:
The first table (the one that has -3 as the first number in the table)
Step-by-step explanation:
A table is a function when the x column doesn't have any numbers repeated.
Evenly divisible means that there is no remainder.
132 is the smallest 3-digit number evenly divisible by 33.
990 is the greatest number evenly divisible by 33.
a 1 = 132, d = 33, a n = 990.
So we have to find n.
a n = a 1 + ( n - 1 ) * d
990 = 132 + ( n - 1 ) * 33
990 = 132 + 33 n - 33
990 = 99 + 33 n
33 n = 990 - 99
33 n = 891
n = 891 : 33 = 27
Answer: There are 27 3-digit numbers that are evenly divisible by 33.
The last one is the function