The temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
Temperature can be represented on a vertical number line with 0 representing 0°F.
Temperatures above 0°F will be located above 0, while temperatures below 0°F will be located below 0.
Given the following temperatures: <em>-3.5℉
, 5℉, 1.5℉, -0.5℉, -2℉, 2.5℉ and -4℉</em>
Therefore, the temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
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brainly.com/question/9291368
The information we have is:
5 drops of flavor are needed for 12 ounces of water.
To solve the problem, first we need to find the amount of drops needed per ounce of water, and then multiply that by the number of ounces that we need which is 1280.
The number of drops per ounce:
To find this, divide 5 drops by 12 ounces:
5/12 drops are needed per ounce.
The number of drops in 1280 ounces:
Now we multiply 5/12 by 1280:
And the result is:
The number of drops needed is: 533.333
Answer: 533.333 Drops
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k