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photoshop1234 [79]
3 years ago
8

Naila wants to use the Babylonian method to estimate the root of 58 to the neatest hundredth. Her initial estimate is 7.8. What

is her estimate after she correctly completes the Babylonian method once?
7.62
7.61
7.44
7.43
Mathematics
2 answers:
JulijaS [17]3 years ago
8 0

Answer:

This question is super old but the answer is actually 7.62

Step-by-step explanation:

Zepler [3.9K]3 years ago
4 0
The answer is 7.61, you could've found the answer for this if you used a calculator.
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12y = 8x + 29 write in slope intercept from and show all your work plz help!
ANTONII [103]

Answer:

2/3x + 29/12

Step-by-step explanation:

<em>P.S Brace yourself cause this is a lot lol :D</em>

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.

y=mx+b

<u>First, you divide each term by 12 and simplify</u>:

Divide each term in 12y = 8x + 29 by 12:

12y/12 = 8x/12 + 29/12

<u>Cancel the common factor of 12:</u>

You do this by dividing 12y/12 leaving you just with y = 8x/12 + 29/12

<u>Then you cancel the common factor of 8 and 12:</u>

You do this by factoring 4 out of 8x:

y = 4 (2x)/12 + 29/12

<u>Then you cancel even more common factors:</u>

Factor 4 out of 12:

y = 4 (2)/ 4 (3) + 29/12

Then you cancel the common factor in that dividion (which is 4) Leaving you with 2x/3 + 29/12

<u>Finally, you rewrite the expression:</u>

y = 2/3x + 29/12

<u></u>

<u></u>

4 0
3 years ago
Find the length of the rectangle if x= 10.
Rama09 [41]

Answer:

34

Step-by-step explanation:

10+2=12

12 on both sides=24

5 on both sides=10

10+24=34

3 0
3 years ago
Calculate the distance between the points H=(3,-1) and E=(8,-5) in the coordinate plane. Give an exact answer (not a decimal app
tester [92]

Answer: \sqrt{41}

===========================================

Work Shown:

Use the distance formula.

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(-1-(-5))^2+(3-8)^2}\\\\d = \sqrt{(-1+5)^2+(3-8)^2}\\\\d = \sqrt{(4)^2+(-5)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41}\\\\

Or you could use the pythagorean theorem, which is how the distance formula is set up.

8 0
3 years ago
A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha
ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                          P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students received a passing grade = 77%

           n = sample of tests = 40

           p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                           level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } , 0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } ]

 = [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0
3 years ago
A board that is 4 1/2 feet long weighs 7 1/5 pounds. How much would one foot of the board
REY [17]

Answer:

A board that is 4 1/2 feet long weighs 7 1/5 pounds. How much would one foot of the board weigh? Write your answer as a mixed number

Step-by-step explanation:

8 0
3 years ago
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