This equation uses y and x so it cannot be factorised.
Let’s try the equation y^2 - 12y + 36 = 0
Look for two factors of 36 that add to -12.
This would be -6 and -6
(y - 6)(y - 6) = 0
(y - 6) must equal 0
y = 6
#13:
s² = 144
√(s²) = √144
|s| = 12
s = -12 OR s = 12
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#15 (not sure what letter you used so I went with 'g')
(g-6)² = 25
√[(g-6)²] = √25
|g-6| = 5
g - 6 = -5 OR g - 6 = 5
g = 1 OR g = 11
Answer:
69 students attend the camp
Step-by-step explanation:
8% of 75 = 6
75 - 6 = 69
Answer: number of tickets sold to adult = 566
Step-by-step explanation:
Let x = number of tickets sold by DCHS to students.
Let y = number of tickets sold DCHS to adults.
Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults.
This means cost of total tickets sold to students and adults is $3x and $5y respectively.
If DCHS collected $3943 for the tickets, then we have
3x + 5y = 3943 - - - - - -1
The number of adult tickets sold was 195 more than the number of student tickets. This means
y = x +195.
Put y = x +195 in equation 1
3x + 5(x+195) = 3943
3x + 5x + 975= 3943
8x +975=3943
8x = 3943-975= 2968
x = 2968/8 = 371
y = 371 + 195= 566
Answer:
The greater the sample size the better is the estimation. A large sample leads to a more accurate result.
Step-by-step explanation:
Consider the table representing the number of heads and tails for all the number of tosses:
Number of tosses n (HEADS) n (TAILS) Ratio
10 3 7 3 : 7
30 14 16 7 : 8
100 60 40 3 : 2
Compute probability of heads for the tosses as follows:

The probability of heads in case of 10 tosses of a coin is -0.20 away from 50/50.

The probability of heads in case of 30 tosses of a coin is -0.033 away from 50/50.

The probability of heads in case of 100 tosses of a coin is 0.10 away from 50/50.
As it can be seen from the above explanation, that as the sample size is increasing the distance between the expected and observed proportion is decreasing.
This happens because, the greater the sample size the better is the estimation. A large sample leads to a more accurate result.