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Temka [501]
3 years ago
14

To test the claim that the resistance of electric wire can be reduced by more than 0.050 ohm by alloying, thirty two (32) values

were obtained for standard wire, and the sample average calculated was equal to 0.136 ohm. In addition, thirty two (32) values were obtained for alloyed wire, and the sample average calculated was equal to 0.083 ohm. The standard deviation resistance for standard wire is known to be 0.004 ohm, whereas the standard deviation resistance for alloyed wire is known to be 0.005. At the level of significance=0.05, does this support the claim?
The z score for this test is z0 =

The p-value for this test is p =

Based on the p-value calculated above, the decision is to fail to reject H0 at a level of significance =0.05 and conclude that the resistance of electric wire can't be reduced by more than 0.05 ohm by alloying. Enter 0 if this statement is FALSE or 1 otherwise:

Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

DEtailed solution is given below:

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AfilCa [17]

Answer:

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Step-by-step explanation:

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3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

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3 0
3 years ago
In the diagram below, we have ST parallel to QR. angle P= 40 degrees, and angle Q= 35 degrees. Find the measure of angles STR in
Drupady [299]

Answer:

m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ

Step-by-step explanation:

<u>Similar Triangles</u>

Lines ST and QR are parallel. Thus, angles S and Q are congruent, and angles T and R are congruent.

Considering the triangle PQR, the sum of its internal angles must be 180°:

m\angle P + m\angle Q + m\angle R = 180^\circ

Substituting the known values:

40^\circ + 35^\circ + m\angle R = 180^\circ

Solving for R:

m\angle R = 180^\circ - 40^\circ - 35^\circ

m\angle R = 105^\circ

Angles S and Q are congruent, thus

m\angle S = 35^\circ

Angles T and R are congruent, thus

m\angle T = 105^\circ

Summarizing:

\mathbf{m\angle S = 35^\circ, \ m\angle T = 105^\circ,\ m\angle R = 105^\circ}

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