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4 years ago

Find an equation for the inverse relation y=-2x+5

Mathematics

1 answer:

Gennadij [26K]4 years ago

6 0

$replace y by x and vice versa, then solve for y:y=-2x+5 \rightarrow x=-2y+5 \implies y=-\frac{1}{2}(x-5)$

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Out of the 30 days in April, 3/5 of the days were sunny and clear. The rest of the days were either cloudy or contained some rai

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Answer:

Step-by-step explanation:

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3 years ago

Solve each given equation and show your work the whether each equation has one solution, an infinite number of solutions, or no

Triss [41]

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2x+4x-4x=2+4
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3 years ago

The area of a round table is 1.13 m2. Find the radius length of

hichkok12 [17]

Answer:

0.6 m

Step-by-step explanation:

-The area of a circular shape is given by the formula:

$A=\pi r^2\\\\\#Where\\r-Radius\\A-Area$

We substitute the given value of area in the formula to solve for Radius:

$A=\pi r^2\\\\1.13=\pi r^2\\\\r=\sqrt{\frac{1.13}{\pi}}\\\\=0.59974\approx0.6\ m$

Hence , the radius length of the table is 0.6 m

5 0

3 years ago

PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.

Step2247 [10]

After using the property of power, the expressions as a power of the number a is $(a^3)^{-2} = a^{-6}$ , $(a^{-1}\cdot a^{-2})^{-3} = a^{9}$ and $((a^2)^{-2})^2=a^{-8}$ .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is $(a^3)^{-2}$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

Simplifying the expression.

$(a^3)^{-2} = a^{3*(-2)}$

$(a^3)^{-2} = a^{-6}$

The second expression is $(a^{-1}\cdot a^{-2})^{-3}$

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}$

Using the property of sum of power $a^m\cdot a^n=a^{m+n}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{9}$

The third expression is $((a^2)^{-2})^2$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=((a^2)^{(-2)\times2})$

$((a^2)^{-2})^2=(a^2)^{-4}$

Again using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=a^{2\times(-4)}$

$((a^2)^{-2})^2=a^{-8}$

To learn more about property of power link is here

brainly.com/question/28747844

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7 0

1 year ago

If twice my age in months is 120, what is then my age in years?

mote1985 [20]

Answer:

Step-by-step explanation:

120/2=60/5=12

8 0

3 years ago