So you would break 247 in to 200,40and 7
u would break 38 into 30 and 8 . so when you as then together you get and sum of 285 .so do you know the strategy now ??
![8 < \sqrt[3]{a} < 9](https://tex.z-dn.net/?f=8%20%3C%20%5Csqrt%5B3%5D%7Ba%7D%20%3C%209)
So, a can be any number between (512, 729).
∴ answer is (A) 679
Answer:
(5x − 4)(x + 2)
Step-by-step explanation:
For the purpose, it is sufficient to make sure the middle terms match.
The middle term in the product of each of the answer choices is ...
-1+40 ≠ 6
-8+5 ≠ 6
-4+10 = 6 . . . . . the third selection is the one you want
-2+20 ≠ 6
<span>The value of the digit in the tenths place is 7. The value of the digit in the hundredths place is 7. The first number to the right of the decimal is in the tenths place and the second number to the right is in the hundredths place. The 0 is in the ones place and is the first number to the left of the decimal.</span>
Answer:
f(2) = -2
Step-by-step explanation:
Substitute 2 everywhere you see an x so f(2) = -2(
) - 2(2) + 10 so
f(2) = -2(4) - 4 + 10, so f(2) = -8-4+10, f(2) = -12+10, f(2) = -2
