y = ∛ (x + 6 - 3) = ∛ (x +3) -----------> graph this
(see attached)
Check: from formula above, when x = -3, y = 0
Check that this point exists on the graph... it does (check OK!)
edit reason: typo
Width: x
Length: 2x
Area=x(2x)=2x^2
2x^2=200
x^2=100
x=10 or -10(reject as x>0) [width cannot be less than 0, doesnt make sense]
Perimeter
=x+x+2x+2x
=6x
=6(10)
=60 yd
Answer:
x=-21
Step-by-step explanation:
x-7=2x+14
-7=x+14
-21=x
<h3>
Answer: Choice B</h3>
c^2-2cd+d^2 = (c-d)^2
We can verify this with the following steps
(c-d)^2 = (c-d)(c-d)
(c-d)^2 = c(c-d) - d(c-d)
(c-d)^2 = c^2-cd-cd+d^2
(c-d)^2 = c^2-2cd+d^2
It is equivalent too 5.3 and 5.30