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KiRa [710]
3 years ago
9

Find the value of x, when log 10x + log 2 = log 60

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

log 10x + log 2 = log 60

Subtract log 2 from each side

log 10x + log 2 -log 2 = log 60 - log 2

log 10x  = log 60 - log 2

We know  that log a - log b = log (a/b)

log 10 x = log (60/2)

log 10x  = log 30

We know log a = log b  that a = b

10x = 30

Divide by 10

10x/10 = 30/10

x =3

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The value of x is 5. Thus, the correct statement is:

x = 5 is a true solution because log subscript 2 Baseline (16) = 4

<h3>Data obtained from the question </h3>
  • Log₂ (x + 11) = 4
  • Value of x =?
<h3>How to determine the value of x </h3>

Log₂ (x + 11) = 4

x + 11 = 2⁴

x + 11 = 16

Collect like terms

x = 16 – 11

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<h3>**Check** </h3>

Log₂ (x + 11) = 4

x = 5

Log₂ (5 + 11) = 4

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x = 5 is a true solution because log subscript 2 Baseline (16) = 4

Complete question

Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4. x + 11 = 2 Superscript 4. x + 11 = 16. x = 5. x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 2 x = 5 is not a true solution because log Subscript 5 Baseline (16) not-equals 4 x = 5 is a true solution because log Subscript 2 Baseline (16) = 4 x = 5 is a true solution because log Subscript 4 Baseline (16) = 2

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