Find the range of the function f(x)=(x-2)^2+2

2 answers:

8 0

The function is in vertex form of a quadratic function.
Vertex form is f(x)=a(x-h)^2+k
The vertex is (h, k)

In this case, our vertex is (2, 2). The a value is positive which means that the graph points up. Since the graph points up, the vertex is the minimum, the lowest point of the graph. The range refers to y-values, so the range of the function is y/y>2. It can also be written as 2≤y<span>≤positive infinity.</span>

Scilla [17]3 years ago

5 0

Answer:

y ≥ 2

Step-by-step explanation:

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