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damaskus [11]
3 years ago
7

Find the range of the function f(x)=(x-2)^2+2

Mathematics
2 answers:
kari74 [83]3 years ago
8 0
The function is in vertex form of a quadratic function.
Vertex form is f(x)=a(x-h)^2+k
The vertex is (h, k)

In this case, our vertex is (2, 2). The a value is positive which means that the graph points up. Since the graph points up, the vertex is the minimum, the lowest point of the graph. The range refers to y-values, so the range of the function is y/y>2. It can also be written as 2≤y<span>≤positive infinity.</span>
Scilla [17]3 years ago
5 0

Answer:

y ≥ 2

Step-by-step explanation:

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3 years ago
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jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

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On dividing both sides by 2 .

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On dividing both sides by 3 .

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Answer:

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Step-by-step explanation:

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3 years ago
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