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In-s [12.5K]
3 years ago
15

Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For

a sorted list of odd length, the median is the middle value. For a sorted list of even length, the median is the average of the two middle values. Make an example function call in your main. Write a function called isSorted that takes an array of doubles as a parameter and returns true if the list is in sorted (non-decreasing) order and returns false otherwise. Make an example function call in your main. Write a function called findCommon that takes three arrays of positive integers as parameters. The first two array parameters are filled with ints. Fill the third array parameter with all the values that are uniquely in common from the first two arrays and the rest of the array with zeros. For example:

Computers and Technology
1 answer:
trapecia [35]3 years ago
8 0

Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

{

if(list[i]>list[i+1])

return false;

}

return true;

}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

{

boolean isFilled=false;

for(int j=0;j<c;j++)

{

if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

{

if(a1[i]==a2[i])

{

common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

{

common[c]=0;

c++;

}

}

public static void rotateRight(int list[])

{

int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

}

list[0]=temp;

}

public static int count(int list[],int n)

{

int ncount=0;

for(int i=0;i<list.length;i++)

{

if(list[i]==n)

ncount++;

}

return ncount;

}

public static int[] stretch(int list[])

{

int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

if(n%2==0)

{

stretchedList[k]=n/2+1;

stretchedList[k+1]=n/2;

}

k+=2;

}

return stretchedList;

}

public static void printDoubleArray(double arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void printIntArray(int arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void main(String[] args)

{

double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

double med=median(list1);

System.out.println("List1:");

printDoubleArray(list1);

System.out.println("Median of List1:"+ med);

double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

printDoubleArray(list2);

System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

int list6[]={3,8,19,7};

System.out.println("\n List6:");

printIntArray(list6);

rotateRight(list6);

System.out.println("\n the array after rotate right:");

printIntArray(list6);

int list7[]={3,5,2,1,92,38,3,14,5,73};

int n=count(list7,3);

System.out.println("\n List7:");

printIntArray(list7);

System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);

int list8[]={18,7,4,24,11};

int list9[]=stretch(list8);

printIntArray(list8);

System.out.println("\n The array after stretching:");

printIntArray(list9);

}

}

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saveliy_v [14]

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Explanation:

In any organization or enterprise it is very essential to provide protection from data loss to avoid breaches by unauthorized accesses and to secure the data irrespective of whether it is in rest or motion.

It is known that data changes its form when it is copied, moved and stored in different memory location so in this process a lot of sensitive data might be exposed to the outside world and left into the hands of the unauthorized for easy of access to it.

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8 0
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You plug a new scanner into a USB port on your Windows system. When you first turn on the scanner, what should you expect to see
Paul [167]

Answer:

A window notifying that: Found New Hardware Wizard

Explanation:

As soon as any device is plugged into the USB port, the default settings will display a window onto the screen which will notify about the addition of a new hardware to the system. This window can further be used to know the properties of the hardware or for configuration settings.

This process is same like the software part, that whenever a new application is installed onto the system a pop up notification alerts about its presence.

So when the scanner will be attached through USB port a window will be appeared notifying about the discovery of new hardware.

3 0
3 years ago
Inc AX,2 is valid in assembly language ?
masya89 [10]

Answer:

in most so yes

Explanation:

4 0
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In 1964 in London, Ontario one could buy a chili-dog and a root beer for $1.25, today the same chili dog and root beer cost $5.0
Marta_Voda [28]

Answer:

3% inflation rise. No correct cpi option

Explanation:

Consumer Price Index(CPI) is calculated by the Bureau of Economic Analysis and Statistics of a country monthly and annually.

Consumer Price Index(CPI) is used for measuring the changes in the price level of consumer goods and services purchased by households.

Calculating the consumer price index; price in 1964= $1.25, today price= $5.0.

Therefore, consumer price index= Price in today- price in 1964÷ price in 1964,.

Consumer Price index(CPI)= $(5-1.25)/1.25 = 3.75/1.25 = 3 Percent price inflation rise.

For the first cpi; 112-80/80= 0.4 percent( not equal to the 3 Percent inflation rise).

For the second cpi: 141.6-60/60= 1.36 Percent inflation rise(not equal to the 3 Percent inflation rise).

For the third CPI: 126.4-75/75 =0.68 percent inflation rise[not equal to the 3 Percent inflation rise].

For the third CPI: 108.5-90/90=0.21 percent inflation rise(not equal to 3 Percent inflation rise)

Therefore, none of the options are right.

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Write the name of the tab, command group, and icon you need to use to access the borders and shading dialog box.
Ilia_Sergeevich [38]

Answer:

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Command group: Paragraph

Icon: Triangle

Explanation:

7 0
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