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In-s [12.5K]
3 years ago
15

Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For

a sorted list of odd length, the median is the middle value. For a sorted list of even length, the median is the average of the two middle values. Make an example function call in your main. Write a function called isSorted that takes an array of doubles as a parameter and returns true if the list is in sorted (non-decreasing) order and returns false otherwise. Make an example function call in your main. Write a function called findCommon that takes three arrays of positive integers as parameters. The first two array parameters are filled with ints. Fill the third array parameter with all the values that are uniquely in common from the first two arrays and the rest of the array with zeros. For example:

Computers and Technology
1 answer:
trapecia [35]3 years ago
8 0

Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

{

if(list[i]>list[i+1])

return false;

}

return true;

}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

{

boolean isFilled=false;

for(int j=0;j<c;j++)

{

if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

{

if(a1[i]==a2[i])

{

common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

{

common[c]=0;

c++;

}

}

public static void rotateRight(int list[])

{

int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

}

list[0]=temp;

}

public static int count(int list[],int n)

{

int ncount=0;

for(int i=0;i<list.length;i++)

{

if(list[i]==n)

ncount++;

}

return ncount;

}

public static int[] stretch(int list[])

{

int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

if(n%2==0)

{

stretchedList[k]=n/2+1;

stretchedList[k+1]=n/2;

}

k+=2;

}

return stretchedList;

}

public static void printDoubleArray(double arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void printIntArray(int arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void main(String[] args)

{

double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

double med=median(list1);

System.out.println("List1:");

printDoubleArray(list1);

System.out.println("Median of List1:"+ med);

double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

printDoubleArray(list2);

System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

int list6[]={3,8,19,7};

System.out.println("\n List6:");

printIntArray(list6);

rotateRight(list6);

System.out.println("\n the array after rotate right:");

printIntArray(list6);

int list7[]={3,5,2,1,92,38,3,14,5,73};

int n=count(list7,3);

System.out.println("\n List7:");

printIntArray(list7);

System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);

int list8[]={18,7,4,24,11};

int list9[]=stretch(list8);

printIntArray(list8);

System.out.println("\n The array after stretching:");

printIntArray(list9);

}

}

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This question is incomplete, here is the complete question:

Python

a) You should create a function that will perform linear interpolation from a set of measured data. The function should take as input a list of values at which samples were taken, and then another list giving the measurements (you can assume each measurement is a single value) at those values. It should also take in a query value, and should give the best estimate it can of the value at that query. Be sure to handle values that are outside of the range, by extrapolating. You should write a program that allows you to test your function by reading the lists from a file where each line of the file is a pair of numbers separated by spaces: the value where the sample was taken, and the measurement at that value. Your program should ask the user for the name of the file and for a query value. Important: The two lists will correspond to each other: i.e. for the i-th value in the first list, the measurement will be the i-th element of the second list (these are called parallel lists or arrays). But, you should not assume that the input values are in increasing/decreasing order. That is, the values in the first list can be in any random ordering, not necessarily from smallest to largest or largest to smallest. You will have to account for this in your program, and there is more than one way to do so. You should discuss what options you can think of to handle the data arriving in any order like that, and decide what you think the best option for handling it is.

Explanation:

from __future__ import division

from cStringIO import StringIO

import numpy as np

from scipy.interpolate import RectBivariateSpline

np.set_printoptions( 1, threshold=100, edgeitems=10, suppress=True )

   # a file inline, for testing --

myfile = StringIO( """

# T P1 P2 P3 P4

0,   80,100,150,200

75, 400,405,415,430

100, 450,456,467,483

150, 500,507,519,536

200, 550,558,571,589

""" )

   # file -> numpy array --

   # (all rows must have the same number of columns)

TPU = np.loadtxt( myfile, delimiter="," )

P = TPU[0,1:] # top row

T = TPU[ 1:,0] # left col

U = TPU[1:,1:] # 4 x 4, 400 .. 589

print "T:", T

print "P:", P

print "U:", U

interpolator = RectBivariateSpline( T, P, U, kx=1, ky=1 ) # 1 bilinear, 3 spline

   # try some t, p --

for t, p in (

   (75, 80),

   (75, 200),

   (87.5, 90),

   (200, 80),

   (200, 90),

   ):

   u = interpolator( t, p )

   print "t %5.1f p %5.1f -> u %5.1f" % (t, p, u)

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