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Nastasia [14]
3 years ago
9

Websites can have good content for a particular set of search phrases, yet rank poorly. Issues that may cause this to occur incl

ude the following, except A. insufficient internal links B. deep organizational structure C. dirty sitemaps with errors or broken links D. having images that contain alt text
Computers and Technology
1 answer:
raketka [301]3 years ago
5 0

Answer:

B. deep organizational structure

Explanation:

A website with a deep organizational structure is a positive attribute that improves site performance.

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In your own words, what is pair-programming? What is the role of the driver? What is the role of the navigator? What are some be
KATRIN_1 [288]

<u>Paired programming:</u>

Paired programming is a new technique where one person gets one another to<em> write the code</em>. Here one will write the code and other will start verifying as the type.

So we might think it is waste to employ two person for same task but it is not so. There are many <em>benefits in incorporating this technique</em>. Let us see those benefits one by one.

  • <em>Inter-personal skill gets improved </em>
  • <em>Lower amount of coding mistake </em>
  • <em>Learn from each other </em>
  • <em>Peer review enhance collaboration </em>

Challenges expect to arise during pair-programming

  • Two heads are superior to one. On the off chance that the driver experiences a <em>hitch with the code</em>, there will be two of them who'll take care of the issue.  
  • Builds up your <em>staff's relational aptitudes</em>. Working together on a solitary venture encourages your group to welcome the estimation of <em>correspondence and collaboration.  </em>

Overcome Method

The most ideal approach to move <em>toward blending</em> is to accomplice two software engineers and have them share a PC. The pair ought to have the option to choose how to part the work, and it is prudent that they should <em>switch jobs frequently.</em>

7 0
3 years ago
Effective nonverbal communication can cause tension.<br><br> True or False
agasfer [191]

Explanation:

When your nonverbal signals match up with the words you're saying, they increase trust, clarity, and rapport. When they don't, they can generate tension, mistrust, and confusion.

4 0
3 years ago
Descuss the five generations of Computer language
Fiesta28 [93]

Answer:

Explanation:

The programming language in terms of their performance reliability and robustness can be grouped into five different generations, First generation languages (1GL) Second generation languages (2GL) Third generation languages (3GL)

6 0
3 years ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
The program that solves problem 2 (a) on p.275 should be named as proj4_a.c. It must include and implement the following functio
avanturin [10]

Answer:

#include <iostream>

#include <cstring>

using namespace std;

bool isAPalindrome(char* palindrome);

int main()

{

   char palindrome[30];

   bool palindrome_check;

   cout << "Please enter an word or phrase.\n";

   cin.getline(palindrome, 30);

   palindrome_check = isAPalindrome(palindrome);

   if (palindrome_check = true)

   {

       cout << "Input is a palindrome\n";

   }

   else

   {

       cout << "Inputis not a palindrome\n;";

   }

system("pause");

return 0;

}

bool isAPalindrome(char* palindrome)

{

   char* front;  

   char* rear;  

front = palindrome;// starts at the left side of the c string

rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s

while (front <= rear)

{

 if (front = rear)

 {

  front++;

  rear--;

 }

 else

 {

  return false;

 }

}

   return true;

}

7 0
3 years ago
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