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3 years ago

What is the expanded form of 3x(x+3)^2=?

Mathematics

1 answer:

il63 [147K]3 years ago

8 0

<span>3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x

answer
</span>3x^3 + 18x^2 + 27x

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[Help asap, question is in image, will mark brainliest]

Misha Larkins [42]

Answer:

V = 339.12

Step-by-step explanation:

Volume of a cone:

V = πr²(h/3)

Given:

r = 6

h = 9

Work:

V = πr²(h/3)

V = 3.14(6²)(9/3)

V = 3.14(36)(3)

V = 113.04(3)

V = 339.12

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3 years ago

Find the equation to the line below!!! Help!

svlad2 [7]

Answer:

y=4/5×-1 is the answer!

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3 years ago

Denise scored 3 fewer points than Carter

ASHA 777 [7]

D = c - 3 Because Denise scored three fewer points than Carter, his score equals Carter's score minus 3. d = 21 - 3 Now, let's substitute in the answer we got for Carter's score. d = 18 Yep! The question says that Denise scored 18 points, so the answer we got is correct.

8 0

3 years ago

If x+y=5,then what is the value of x3+y3+15xy

a_sh-v [17]

Answer:

125

Step-by-step explanation:

x + y = 5

We need to have x^3 and y^3 in the expression, so cube both sides.

(x + y)^3 = 5^3

Expand the left side.

(x + y)(x + y)^2 = 125

(x + y)(x^2 + 2xy + y^2) = 125

x^3 + 2x^2y + xy^2 + x^2y + 2xy^2 + y^3 = 125

x^3 + 3x^2y + 3xy^2 + y^3 = 125

Now we need to separate x^3 + y^3.

x^3 + y^3 + 3x^2y + 3xy^2 = 125

We need to turn 3x^2y + 3xy^2 into 15xy.

Factor the GCF, 3xy, out of 3x^2y + 3xy^2.

x^3 + y^3 + 3xy(x + y) = 125

We know that x + y = 5, so substitute x + y with 5.

x^3 + y^3 + 3xy(5) = 125

x^3 + y^3 + 15xy = 125

Answer: 125

5 0

3 years ago

29. BASKETBALL When Jerald shoots a free throw, the ball is 6 feet from the floor and has

tatuchka [14]

Answer:

a) j(t) = -16t^2 +20t +6

b) 1 second

c) less time

Step-by-step explanation:

The general equation for vertical motion is ...

$h(t)=-\dfrac{1}{2}gt^2+v_0t+h_0\\\text{where $v_0$ is the initial upward velocity, and $h_0$ is the initial height}$

a) j(t) = -16t^2 +20t +6 . . . . . filling in the given initial values, with g=32 ft/s^2

b) We want to find the larger of the solutions to ...

j(t) = 10 = -16t^2 +20t +6

Subtracting 6 and dividing by -4, we have ...

-1 = 4t^2 -5t

4t^2 -5t +1 = 0 . . . . add 1, put in standard form

(4t -1)(t -1) = 0 . . . . . factor

t = 1/4 or 1

The ball is in the air 1 second before reaching the hoop.

c) In generic terms, the equation of motion for a given shooting height at the same upward velocity will be ...

10 = -16t^2 +20t + h0

-16t^2 +20t +(h0 -10) = 0

Using the quadratic formula, we find the larger solution to be ...

t = (-(20) -√(20² -4(-16)(h0 -10)))/(2(-16))

t = (5/8) + √(64h0 -240)/32 = (5 +√(4h0 -15))/8

This value increases as h0 increases, so the ball will be in the air less time when Raymond shoots.

7 0

4 years ago