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3 years ago

Use any method to solve the equation. If necessary, round to the nearest hundredth.7x2 − 16x = 8

1 answer:

4 0

7x^2 - 16x - 8 = 0

using the quadratic formula x = [ -(-16)+/- sqrt((-16^2 - 4*7-8] / 2*7

= (16 +/1 sqrt 480) / 14

= 2.71, -0.42 to nearest hundredth

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Is 3.03003000300003... a repeating decimal

SVETLANKA909090 [29]

The answer is no because after each 3 there is one more zero added

to be repeating the number of zeros would have to stay the same

8 0

3 years ago

Two runners start 30kilometer apart and run toward each other. they meet after 3hours. One Runner runs 2 kilometers per hour fas

joja [24]

Answer:

4 km per hour and 6 km per hour.

Step-by-step explanation:

The combined running rate = 30/3 = 10 km/h.

If one runner's speed = x then the other one's speed is x+2 km/h.

So x + x + 2 = 10

2x = 8

x = 4

So one runs at 4 km/h and the other at 6 km/h.

3 0

3 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago

Does the point(1, 8)satisfy the inequality y ≥ 6x + 2 ?

nalin [4]

Answer: Yes

Step-by-step explanation:

1. Substitute 1 for x

2. 6 times 1 is 6 plus 2 is 8

3.8 is equal to or greater than 8

4 0

3 years ago

116.PS-9 Question Help Find the surface area of the prism. 8 cm 5 cm13cm 12 cm

Ivanshal [37]

Answer:

6,240 cm

Step-by-step explanation:

8 cm x 5 cm x 13 cm x 12 cm = 6,240 cm

8 0

3 years ago