Question

Find the range for the function k(n) = 2n2 when D = {–2, 1, 3}. R = {2, 8, 18} R = {2, 18, 36} R = {4, 12, 27} R = {4, 12, 16}

Answer 1

K(n) = 2n^2.....where domain (n) = -2
k(-2) = 2(-2^2) = 2(4) = 8

k(n) = 2n^2.....where n = 1
k(1) = 2(1^2) = 2(1) = 2

k(n) = 2n^2...where n = 3
k(3) = 2(3^2) = 2(9) = 18

so ur range k(n) = { 2,8,18}

Answer 2

Answer:

The correct option is 1.

Step-by-step explanation:

The given function is

$k(n)=2(n^2)$

Domain is the set of input values and range is the set of output values.

It is given that the domain of the function is D = {–2, 1, 3}.

Substitute n=-2 in the given function.

$k(-2)=2((-2)^2)=2(4)=8$

Substitute n=1 in the given function.

$k(1)=2(1^2)=2(1)=2$

Substitute n=3 in the given function.

$k(3)=2(3^2)=2(9)=18$

The set of output values is {8, 2, 18}. So, the range of the function is

R = {2, 8, 18}

Therefore the correct option is 1.