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2 years ago

6(-1/2)-2 I need work also

Mathematics

1 answer:

Slav-nsk [51]2 years ago

6 0

Answer:

6(−1/2)−2

=−3−2

=−5

Step-by-step explanation:

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woman has 7 coworkers' man. How many different possible groups of four people could do the project, if one out of three is women

aliina [53]

Answer: 24ways

Step-by-step explanation:

Given data:

No of men in the workplace = 7

No of women in the workplace = 1

How many ways can a group of 4 people carry out a project if on out of the 3 must be a woman.

Solution.

A group of 4 can carry out the project with one be a woman

This means there must be 3 males and 1 female in the group

= 4p3

= 24ways

The project can be carried out by 4 groups in 24 ways

6 0

2 years ago

What is the mean of -9,-5,-4,-4,-2,0,1,2,3,5

IrinaK [193]

Answer: - 1.3

Step-by-step explanation: I believe that it's -1.3 if you're referring to the arithmetic mean.

(1) Take the sum of -9, -5, -4, -4, -2, 0, 1, 2, 3, 5 and simplify it to -13

(2) Count the number of terms in the data set.

{-9, -5, -4, -4, -2, 0, 1, 2, 3, 5}

{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} - The number of terms in the data set is <u>10.</u>

(3) Divide the sum by the number of terms and simplify.

-13 / 10 = -1.3 (simplified)

8 0

2 years ago

Someone help me please and thank you!! ASAP :(

pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$

We must require that $x \ne -12$ and $x \ne 3$ to avoid having 0 in the denominator. This is why choice D is the answer.

3 0

2 years ago

Six ways to add 6, 7 and 8

Alexxandr [17]

6+7+8
6+8+7
7+6+8
7+8+6
8+7+6
8+6+7

8 0

3 years ago

Read 2 more answers

Your firm has a contract to make staff uniforms for a fast-food retailer. The heights of the staff are normally distributed with

FromTheMoon [43]

Answer:

a) 16%

b) 2.5%

Step-by-step explanation:

The mean is 70 with standard deviation(SD) of 3 and you are asked to find out the percentage of staff that have <67(70-3 inch= mean - 1 SD) inch size, which means 1 SD below the mean (<-1 SD). Using 68-95-99.7 rule, you can know that 68% of the population is inside 1 SD range from the mean ( -1 SD to + 1 SD).

To put it on another perspective, there are 32% of the population that have < -1 SD and > +1 SD value. Assuming the distribution is symmetrical, then the value of < - 1 SD alone is 32%/2= 16%

The question asks how many populations have size >76 inches, or mean + 2 SD (70+3*2 inch).

You can also solve this using 68-95-99.7 rule, but you take 95% value as the question asking for 2 SD instead. Since 95% of population is inside 2 SD range from the mean ( -2 SD to + 2 SD), so there are 5% of population that have < -2 SD and > +2 SD value. Assuming the distribution is symmetrical, then the value of > +2 SD alone is 5%/2= 2.5%

3 0

2 years ago