THE STATEMENT IS TRUE.
MULTIPLICATION<span> AND DIVISION: When </span>multiplying<span> or dividing numbers, count the NUMBER OF </span>SIGNIFICANT FIGURES<span>. The answer cannot CONTAIN MORE </span>SIGNIFICANT FIGURES<span> THAN THE NUMBER BEING MULTIPLIED OR DIVIDED with the LEAST NUMBER OF</span>SIGNIFICANT FIGURES<span>.
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Can you put more information into this question
Answer:
option B (28/52)
Step-by-step explanation:
from probability
P(A∪B)=P(A)+P(B)-P(A∩B)
where
P(A∪B) = probability that event A or B happen
P(A∩B) = probability that event A and B happen simultaneously
P(A) = probability that event A happen
P(B) = probability that event B happen
the probability that the card is special or red
P( special or red)= P(special) + P(red) - P( special and red)
since
P(special)= 4/52
P(red) = 26/52
P( special and red) = 2/52
therefore
P( special or red)= 4/52 + 26/52 - 2/52 = 28/52
P( special or red)= 28/52
(option B)
Given:
Entrance fee per student: $5(29)
Lunch costs: $4(29 + 6)
Bus fees: $25 + 8($2 + $3)
Total cost: 5(29) + 4(35) + 25 + 8(5)
To find:
The equivalent expressions of the total cost that use the properties of operations to simplify the math.
Solution:
We have,
Total cost = 5(29) + 4(35) + 25 + 8(5)
To simply this expression, we need to write 29 and 35 in the expand form or as the sum of their place values because it is easy to multiply a number with multiply of 10 and single digit.
Total cost = 5(20+9) + 4(30+5) + 25 + 40
Therefore, the correct option is B.
