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AfilCa [17]
2 years ago
13

6c*2-5d + 8= When c= 5 and d= 4?? Help I’m in class PLEASE

Mathematics
1 answer:
BartSMP [9]2 years ago
3 0

Step-by-step explanation:

hope this helped :))) !!

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24*43x22*8x67x890x10*3x6*1x8*1
lukranit [14]

Answer:

1032x176x67x890x30x6x8

1032×176×67×890×30×6×8x^6

1.56^13×x^6

4 0
2 years ago
What is 7 and 1/2 minus 3/4
Sliva [168]

Answer:

here's your answer in the given picture

8 0
2 years ago
12x +18<br> :)<br> 6<br> what’s the work
slava [35]

Answer:

6(2x+3)

Step-by-step explanation:

12x +18

Factor out 6 from each term

6*2x+ 6*3

6(2x+3)

6 0
3 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

4 0
3 years ago
I don’t understand the equation
ankoles [38]

you need to find to find the value of x and y.

2x>(-15-5y)

x>(-15-5y)/2

now put this in to other equation and solve for y and then put the y value in and find x.

6 0
3 years ago
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