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3 years ago

Can i please get help with this Question?

Mathematics

1 answer:

sashaice [31]3 years ago

3 0

So firstly, I'm going to be converting the mixed number into an improper fraction. To do this, multiply the whole number by the denominator and then add that product with the numerator and that will be your new numerator. In this case:

3 × 8 = 24, 24 + 3 = 27. $\frac{-27}{8}$

Now since they have the same denominator, you can subtract the numerators.

$\frac{-27}{8}-\frac{7}{8}=\frac{-34}{8}$

Now simplify the number as such:

$\frac{-34}{8}\div\frac{2}{2}=\frac{-17}{4}$

<u>In short, your answer is -17/4, or -4 1/4.</u>

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Drew invests $4000 at 6% for 5 years. How much interest does Drew earn? Remember the formula for simple interest is I=prt.

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Answer:

I = $1,200.00

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year,

then, solving our equation

I = 4000 × 0.06 × 5 = 1200

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3 years ago

A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee

madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

Step-by-step explanation:

We are given that a class has 35 students

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Number of female=19

We have to choose 6 students for committee

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Probability=P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

$nC_r=\frac{n!}{r!(n-r)!}$

Using the formula

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

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3 years ago

Determine whether the statement is always true, sometimes true, or never true. Give an example. (a) Both sides of an equation ca

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Answer:

(A) Always true

(B) Seldom true

Step-by-step explanation:

(A) Both sides of an equation can be multiplied by the same number without this action changing the solution of the equation.

Keyword here is "number".

Multiplying both sides of an equation by an equal quantity (same number) will result in same solution after solving for the unknown in the equation. This is because that numeric quantity can always be removed by dividing both sides of the equation by it or by a factor (or multiple) of it.

EXAMPLE:

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let's find the solution, in other words solve for the unknown value X.

4x - 15x = 6

-11x = 6

x = -6/11

Now multiply both sides of the equation by 3.

3(4x - 6) = 3(15x)

12x - 18 = 45x ___new equation

Solve for X

12x - 45x = 18

-33x = 18

x = -18/33

Reduce the fraction to its simplest form by looking for a number that can divide both numerator and denominator without remainder. In other words, think of a number that is a factor of 18 and a factor of 33.

That common factor or highest common factor (HCF) is 3.

Go ahead and reduce the fraction.

x will be reduced to -6/11

(B) Both sides of an inequality can seldom be multiplied by the same number, without such action changing the solution set of the equation.

Inequalities are more complex. Operational signs even change sometimes, in the course of finding the solution set of the inequality.

Sometimes, multiplying both sides of an inequality by a given numeric quantity will change its solution set and sometimes, it won't.

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