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muminat
3 years ago
9

341.84-21.92 show my work

Mathematics
2 answers:
dsp733 years ago
7 0
341.84
-21.92
319.92
gogolik [260]3 years ago
5 0

341.84

-

21.92

_________

319.92

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Choose all that give the correct expression for the quantity described.
dmitriy555 [2]

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Its D on e2020

Step-by-step explanation:

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Help, I’m a bit confused, what would the coordinates be. The question is in the picture!!!!!
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(x+4), (y-1) because the figure is translated 4 units to the right and 1 down.
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Solve the system of equations. <br>5y-4x = -7 <br>2y+4y = 14​
timofeeve [1]

Answer:

5y-4x= -7 :

Slope = \frac{1.600}{2.000} = 0.800

<em>x </em>- <em>intercept =  </em>\frac{7}{4} = 1.75000

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----------------------------------------------

2y+4y = 14 :

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<em>Hope this helped & good luck <333</em>

3 0
2 years ago
Relationships in Figures
N76 [4]

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Step-by-step explanation:

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3 years ago
Verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial
Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

7 0
3 years ago
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