Given: 2x - 3y = -6 ⇒ identified as 1st equation x + 2y = 8 ⇒ identified as 2nd equation
Let us first get the value of x using the 2nd equation. x + 2y = 8 x = 8 - 2y
Substitute x in the 1st equation with its value and find the value of y. 2x - 3y = -6 2(8-2y) - 3y = -6 16 - 4y -3y = -6 -4y - 3y = -6 -16 -7y = - 22 y = -22/-7 y = 22/7 simplified to 3 1/7
Substitute the value of y in the 2nd equation. x = 8 - 2y x = 8 - 2(22/7) x = 8 - 44/7 x = (8 * 7/7) - 44/7 x = 56/7 - 44/7 x = (56-44)/7 x = 12/7 simplified to 1 5/7
To check: x = 12/7 and y = 22/7 *we need to use the improper fractions. 2x - 3y = -6 2(12/7) - 3(22/7) = -6 24/7 - 66/7 = -6 (24-66)/7 = -6 -42/7 = -6 -6 = -6
