The awnser is 9.48683298051, hope I helped!
Answer:
217
Step-by-step explanation:
124%=x
36%=63
=>
Here is an attachment with the answer. I hope this helps.
Answer: The shaded area is 99.55 units squared.
Step-by-step explanation:
r = 3.2
Now, we can see that the sides of the square are equal to two times the diameter of the circles (or four times the radius of the circles), so the length of the sides of the square is:
L = 2*(2*3.2) = 12.8
The area of the square is A1 = L^2 = 12.8*12.8 = 163.84 units squared.
the shaded semicircle has a diameter of 4 times r (so the radius is 2 times r), and the area is equal to half the area of a circle:
A2 = (1/2)*pi*(2r)^2 = (1/2)*3.14*(6.4)^2 = 64.31 units squared.
And now we must subtract the area of the four smaller circles inside the square, the area of each one is:
A3 = pi*r^2 = 3.14*(3.2)^2 = 32.15 units squared.
Then the shaded area is:
A = A1 + A2 - 4*A3 = 163.84 + 64.31 - 4* 32.15 = 99.55 units squared.
Answer:
The ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.
Step-by-step explanation:
Let the Area of smaller watch face be 
Also Let the Area of Larger watch face be 
Also Let the radius of smaller watch face be 
Also Let the radius of Larger watch face be 
Now given:

We need to find the ratio of the radius of the smaller watch face to the radius of the larger watch face.
Solution:
Since the watch face is in circular form.
Then we can say that;
Area of the circle is equal 'π' times square of the radius 'r'.
framing in equation form we get;


So we get;

Substituting the value we get;

Now 'π' from numerator and denominator gets cancelled.

Now Taking square roots on both side we get;

Hence the ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.