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chubhunter [2.5K]
3 years ago
15

Dirk ordered a circular pizza that was 16 inches wide. If dirk ate a quarter of the pizza how many square inches of the pizza di

d he eat?
Mathematics
2 answers:
svetlana [45]3 years ago
4 0
4 inches. You divide 16 by 4 because a something in quarters is 4 pieces.
harkovskaia [24]3 years ago
3 0
50.25
you have to find the area of the pizza first.
to do that you take half of the diameter 16
to get the radius 8
once you have the radius you square it 8*8 = 64
you than multiply it by pie 3.14
and get 200.95 or if you round 201
if you rounded you would get 50.25 if you didn't
than you would get. 50.24
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Use exponents to write each expression. Then evaluate the expression. 3x3x3x3x3
nalin [4]

Step-by-step explanation:

3 to the power of 5

3^5

= 3x3x3x3x3

= 243

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2 years ago
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Given 2x^2=-8, x is<br><br> A.-2<br> B. 2<br> C. 2i or -2i<br> D. 4i or -4i
Lera25 [3.4K]

Answer:

2i or -2i

Step-by-step explanation:

2x² = -8     First, clear x.

x² = -8/2    Solve

x² = -4        Now, eliminate the square of x by solving the square root of -4.

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3 years ago
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Determine whether y = -2x² - 3 is a function.
Alexus [3.1K]

Answer:yes

Step-by-step explanation:

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2 years ago
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
What is a good estimate for this angle measurement?
Ivan

Answer: I would say 135

Step-by-step explanation:

4 0
3 years ago
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