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Nataly [62]
4 years ago
11

What is the best way to be successful in an examination which will be done before 1 month? ​

SAT
1 answer:
steposvetlana [31]4 years ago
4 0

Answer:

According to my experience, revising the chapters before 1 month would really be beneficial. If you have the habit of following time table then you can make one and set the target to finish the syllabus right 3 or 4 days before examination which would make you feel confident. Find your distraction factor and try your best to avoid it. Practicing maths at night and reading the other subjects at morning will be more suitable. You can write the things on your rough copy which would really help you to memorize for language subject. And for maths you may start from the easy questions and you may go to difficult ones. That will help you somehow to develop interest. Dont choose a place like bed to study. Sit in such place where you won't feel sleepy. Dont feel pressurize while reading.

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What is the simplified form of ? 5000 5000 100 100.
Reptile [31]

Answer:

um are they four different nos. if so then

5×10 to the power of 3 for the first two

1× 10 to the power of 2 for the second two

but if the are one number then

5× 10 to the powers of 13 since u didn't state to which form I put it in standard form your welcome

8 0
3 years ago
PLEASEEE HELPPP ASAP I WILL GIVE BRAINLSIT There is pollution that has spilled into a lake. Explain why the birds who live on th
BlackZzzverrR [31]
Answer:

The birds are more likely to survive than the fish because the fish actually live in the lake and get resources from there. If the lake gets polluted, the water, oxygen, and food will get worse and the fish will slowly start to die. But the birds can just look for their resources somewhere else.
3 0
3 years ago
A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t
OLga [1]

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 \frac{m}{s}.

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f1=f\frac{v+-vR}{v+-vE}

Where:

  1. f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  2. v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
  3. vR, vE: Speed ​​of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
  4. ±, ∓:
  • We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

  • We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

  • f1= 30,000 Hz + 900 Hz= 30,900 Hz
  • f= 30,000 Hz
  • v= 340 m/s
  • vE=vR= vbat
  • Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

Solving:

\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03×( 340\frac{m}{s} -vbat)= 340 \frac{m}{s} + vbat

1.03×340\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 340 \frac{m}{s}= vbat + 1.03×vbat

10.2 \frac{m}{s}= 2.03×vbat

10.2 \frac{m}{s}÷ 2.03 = vbat

<u><em>5.02 </em></u>\frac{m}{s}<u><em>= vbat</em></u>

In summary, the speed of the bat is closest to 5.02 \frac{m}{s}.

Learn more about the Doppler effect:

  • brainly.com/question/17107808
  • brainly.com/question/14929897
6 0
2 years ago
What was 6the major provision of the Gulf of Tonkin Resolution? What was the gulf to Tonkin resolution what the answer is
ziro4ka [17]
On August 7, 1964, Congress passed the Gulf of Tonkin Resolution, authorizing President Johnson to take any measures he believed were necessary to retaliate and to promote the maintenance of international peace and security in southeast Asia.

Tonkin Gulf Resolution

Authority granted by congress to President Johnson in 1964 to approve and support in advance " The determination of the president as commander in Chief, to take all necessary measures to repel any armed attacks against the U.S.

hope this helps.
6 0
3 years ago
Which of the following is an example of a short-term goal?
Ghella [55]

Assuming your retirement is more than 2 years away, and that your car purchase is not before the end of the year, the shortest-term goal of those listed is ...

... d. add $200 to your savings account by the end of the year

_____

As a teenager, "short term" may be a matter of a week or two. As a middle-aged adult, both your life-lived and life-expectancy are somwhat longer, so "short-term" can be somewhat longer as well. In old age and failing health, "short-term" may again be a matter of a few weeks at most. Such concepts are tempered by perspective.

7 0
3 years ago
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