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3 years ago

Living organisms release carbon dioxide _____.

SAT

2 answers:

slava [35]3 years ago

8 0

Living organisms release carbon dioxide to producers

Setler79 [48]3 years ago

8 0

Hello there!

Carbon dioxide is released from the body when organisms breathe out, or exhale. Plants need carbon dioxide to make their own food, and they release oxygen in the process. Oxygen is also found in the air. Organisms like plants and green algae make their own food.

That being said, Living organisms release carbon dioxide to producers!

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For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an

Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

$\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}$

where;

n = Number of electrons = 2
$\mathbf{E_o}$ = Initial voltage = 0.77 V
$\mathbf{E_{cell}}$ = Cell voltage = 0.78 V
$\mathbf{[Mn^{2+}]}$ = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

$\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}$

$\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}$

$\mathbf{Fe^{2+} =0.02297 \ M }$

Learn more about using the Nernst equation here:

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