Answer:
There is not enough evidence to support the executive's claim that the percentage is actually different from the reported percentage of 26%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 100
p = 26% = 0.26
Alpha, α = 0.01
First, we design the null and the alternate hypothesis
This is a two-tailed test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from the table.
P-value = 0.040267
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.
Thus, there is not enough evidence to support the executive's claim that the percentage is actually different from the reported percentage of 26%.
Given:
Total number of tickets = 353
Single ticket = $92
Family ticket = $122
Total sales = $39946
To find:
The number of family tickets.
Solution:
Let x be the number of single tickets and y be the number of family tickets.
Total tickets: ...(i)
Total sales: ...(ii)
Multiply (i) by 92 and subtract the result from (ii).
Divide both sides by 30.
Therefore, the number of family tickets is 249.
I know A is one of the correct answers, I’m not sure about the others