Complete the table.
1 answer:
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Hey There!
First you would need to factor out the two.
-4x^3/2 = -2x^3
2x^2/2= x^2
12x/2= 6x
6/2= 3
Now we have.
-2x^3+x^2+6x+3 / x+1
We would then factor with polynomial division, and then we should have.
-2(2x^2 - 3x - 3)(x+1) / x+1
We would then cancel out the x+1
Therefore, the answer would be
Hope this helped!
The correct answer is: [C]: " a = ± 
" .
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:
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</span>→ " 25 = a² + b² " ; Solve for "a" ;
_________________________________________________________
→ To solve for "a" ; we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite: " 25 = a² + b² " ;
as: " a² + b² = 25 " .
_________________________________________________________
Then, we can subtract " b² " from each side of the equation; as follows:
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→ " a² + b² − b² = 25 − b² " ;
to get:
_________________________________________________________
→ " a² = 25 − b² " ;
_________________________________________________________
→ Now, take the square root of EACH SIDE of the equation ;
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ;
_________________________________________________________
→ √(a²) =
;
to get:
_____________________________________________________
→ a = | | ;
→ a = ± ;
→ which is: Answer choice: [C]: " a = ± " .
______________________________________________________
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:
_________________________________________________________
</span>→ " 25 = a² + b² " ; Solve for "a" ;
_________________________________________________________
→ To solve for "a" ; we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite: " 25 = a² + b² " ;
as: " a² + b² = 25 " .
_________________________________________________________
Then, we can subtract " b² " from each side of the equation; as follows:
_________________________________________________________
→ " a² + b² − b² = 25 − b² " ;
to get:
_________________________________________________________
→ " a² = 25 − b² " ;
_________________________________________________________
→ Now, take the square root of EACH SIDE of the equation ;
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ;
_________________________________________________________
→ √(a²) =
to get:
_____________________________________________________
→ a = |
→ a = ±
→ which is: Answer choice: [C]: " a = ±
______________________________________________________