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2 years ago

What is the range of y equals log 8 x

Mathematics

1 answer:

azamat2 years ago

4 0

Answer:

(-∞, ∞)

Step-by-step explanation:

The range of any log function is <em>all real numbers</em>.

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Over what interval is the function nonlinear?

inna [77]

Answer:

Step-by-step explanation:

3rd one

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2 years ago

Leslie bought 6 watermelons the weighed 3 5/8 pounds each. How much did weigh all together?

VashaNatasha [74]

Answer:

The answer is 105/4

Step-by-step explanation:

$6 \times \frac{35}{8} = \frac{3 \times 35}{4} = \frac{105}{4}$

6 0

2 years ago

Read 2 more answers

Write an expression that represents the product of q and 8, divided by 4.

Sholpan [36]

Answer:

8 q / 4 =2q

Step-by-step explanation

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3 years ago

2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver

timofeeve [1]

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$y = 2x^{2} - 9x - 56$

$2x^{2} - 9x - 56 = 0$

$a = 2, b = -9, c = -56$

Then

$\bigtriangleup = b^{2} - 4ac = (-9)^{2} - 4*2(-56) = 529$

$x_{1} = \frac{-(-9) + \sqrt{529}}{2*2} = 8$

$x_{2} = \frac{-(-9) - \sqrt{529}}{2*2} = -3.5$

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

7 0

3 years ago

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$ m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

7 0

3 years ago