Answer:
oop lol i must be a rat then
Step-by-step explanation:
Answer:
15.1
Step-by-step explanation:
29.34
-14.24
---------
15.10
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Hi there!
Something really good to remember about trigonometry is SOHCAHTOA. I won’t dive into too much detail about it, but you should google it for future assignments.
Anyways,
tan50°=14/AB
ABtan50°=14
AB=14/tan50°
AB=11.75
cos50°=14/AC
ACcos50°=14
AC=14/cos50°
AC=21.78
For the measure of angle C you can use a theorem called the third angle theorem. In every single possible triangle, the sum of all three angles adds up to 180°. You can set up an equation like so...
angleC=180-(90+50)
angleC=180-140
angleC=40°
