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4 years ago

11

there are 16 sixth graders and 20 seventh graders in the robotics club. Wants to organize the club members into equal size each

group will only have 6 th graders and 7 th graders

1 answer:

lina2011 [118]4 years ago

7 0

the answer is 4 because 16 and 20 can both be divided by 4.

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Cmiller31<br><br> 6(5 x 37 + 94) + 72 x 3

timofeeve [1]

This answer to this problem is 1890

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2 years ago

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NEED HELP 25 POINTS PLEASE HELP.The students at Harrison Middle School are being split into groups for a community service proje

belka [17]

Each group will have the same number of boys and girls in a group. Find common factors for the number of boys and girls.

6th grade :
64 girls = 8 * 8
72 boys = 8 * 9
There will be 8 groups consisting of 8 girls and 9 boys

7th grade :
81 girls = 9 * 9
63 boys = 9 * 7
There will be 9 groups consisting of 9 girls and 7 boys

8th grade :
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60 boys = 4 * 12
There will be 4 groups consisting of 17 girls and 12 boys

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4 years ago

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Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

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8 0

2 years ago

What is the next letter? azbycxd

elixir [45]

The next letter is w because it is the same distance form the middle as d

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3 years ago

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Help me please i really need it I need solution.

Strike441 [17]

Answer:

30 are present and 10 are absent

Step-by-step explanation:

75% of 40 is 30

Therefore 30 pupils are present

And 10 pupils are absent

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3 years ago

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