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Lilit [14]
3 years ago
12

If John bought two oranges and David bought 6 oranges, how many more oranges did David by than John

Mathematics
2 answers:
CaHeK987 [17]3 years ago
4 0

Answer:

4

Step-by-step explanation:

bija089 [108]3 years ago
4 0

Answer:

4 oranges

Step-by-step explanation:

6-2=4

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50,000 is the nearest ten thousand.
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Which is the 9th term of the sequence which has a first term of 1 and has a common ratio of 1.5
noname [10]
Hey!
So what you can do is:
1 x 1.5 = 1.5(2nd term)
1.5 x 1.5=2.25(3rd term) x 1.5=3.375(4th term) x 1.5 = 5.0625(5th term)

5.0625 x 1.5=7.59375(6th term)x1.5=<span> 11.390625

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The answer is D!
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4 years ago
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When an amount of heat Q (in kcal) is added to a unit mass (kg) of a
lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71.\overline {6} °C/min

Step-by-step explanation:

The given parameters of the question are;

The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)

The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)

\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)

Therefore, we get;

\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}

\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C }   = 71.\overline 6 \, ^{\circ } C/min

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

\dfrac{dT}{dt}  = 71.\overline 6 \, ^{\circ } C/min

8 0
3 years ago
On last week's climb, each climber carried a pack that was 28% of his or her body weight. One climber weighed 78 pounds. What wa
11Alexandr11 [23.1K]
<h3><u>Solution</u> : </h3>

weight of bag :

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13. What is the absolute value of -32?
kozerog [31]

Answer:

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