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andrew11 [14]
4 years ago
11

Alan used the expression StartFraction 5 over 9 EndFraction (F minus 32), where F is a temperature in degrees Fahrenheit, to con

vert a temperature from Fahrenheit to Celsius. He evaluated the expression as shown below and found that 45 degrees Fahrenheit was equivalent to –7 degrees Celsius.
StartFraction 5 over 9 EndFraction (F minus 32) = StartFraction 5 over 9 (45 minus 32) = 25 minus 32 = negative 7


What error did Alan make?

He substituted 45 for F instead of –7 and should have found the answer to be Negative 21 and two-thirds degrees Celsius.

He did not combine within the parentheses first before multiplying and should have found the answer to be 7 and StartFraction 2 over 9 EndFraction degrees Celsius.

He multiplied 45 by the fraction incorrectly and should have found the answer to be 49 degrees Celsius.

He divided 5F by 9 before subtracting 32 and should have found the answer to be 21 and StartFraction 4 over 9 EndFraction degrees Celsius.
Mathematics
2 answers:
Elanso [62]4 years ago
7 0

Answer:

Im making it easier for everyone by just saying what it is. its BBBBBBBB

Step-by-step explanation:

Ymorist [56]4 years ago
4 0

C=\frac{5}{9} (F-32)     [C = Celsius    F = Fahrenheit]

Alan found 45°F = -7°C, his work:

C=\frac{5}{9} (F-32)=\frac{5}{9} (45-32)=25-32=-7

So he distributed 5/9 into (45 - 32), but he only distributed it to 45. It would've been:

C=\frac{5}{9} (45-32)=(\frac{5}{9} )45+(\frac{5}{9} )(-32)=25-\frac{160}{9} =\frac{65}{9}

What error did Alan make?

#1: He substituted 45 for F instead of –7 and should have found the answer to be Negative 21 and two-thirds degrees Celsius.

This is wrong because he used 45 degrees Fahrenheit, not -7 degrees Fahrenheit.

#2: He did not combine within the parentheses first before multiplying and should have found the answer to be 7 and StartFraction 2 over 9 EndFraction degrees Celsius.

This is right because he should've combined inside the parentheses first before multiplying the fraction.

C=\frac{5}{9} (45-32)=\frac{5}{9} (13)=\frac{65}{9} =7\frac{2}{9}

#3: He multiplied 45 by the fraction incorrectly and should have found the answer to be 49 degrees Celsius.

This is wrong because 45 multiplied by the fraction does = 25

#4: He divided 5F by 9 before subtracting 32 and should have found the answer to be 21 and StartFraction 4 over 9 EndFraction degrees Celsius.

This is wrong because he didn't do this

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see the attached figure to better understand the problem

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y-------> the width side of a rectangle

we know that

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AB=DC=x\\AD=BC=y

Step 1

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we know that

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d=\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}

substitute the values

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we know that

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d=\sqrt{(y2-y1)^{2} +(x2-x1)^{2}}

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