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Basile [38]
3 years ago
7

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0

Answer:

7.1

Step-by-step explanation:

d = sqrt(7^2 + -1^2)= sqrt(50)=7.1

neonofarm [45]3 years ago
6 0

Answer:

by using distance formula

putting values

d=√(-1-6)²+(-4--5)²

d=√(-7)²+(1)²

d=√49+1

d=√50

d=5√2=7.1

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Sandra has $500 in a savings account that earns 1% annual interest. She
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The purchasing power of Sandra's savings according to the description above has decreased.

<h3>What happens to the purchasing power of Sandra's savings?</h3>

It follows from the task content that Sandra's savings attracted an annual interest rate of 1% while the inflation is 2% per annum. On this note, it follows that Sandra's savings purchasing power has reduced as the prices of commodities have gone up and the interest rate is unable to match it.

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2 years ago
Help me with this please!!
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3 years ago
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7 0
3 years ago
4. As part of a promotion for a new type of cracker, free samples are offered to shoppers in a local supermarket. The probabilit
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Answer:

For this case we need to check the conditions in order to use the normal approximation:

1) np = 60*0.3= 18>10

2) n(1-p) = 60*(1-0.3)= 42>10

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})

The mean would be given by:

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And the deviation is given by:

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Step-by-step explanation:

For this case we know the following info:

n =60 represent the sample size

\hat p = 0.3 represent the estimated proportion of people that will buy a packet of crackers after tasting

For this case we need to check the conditions in order to use the normal approximation:

1) np = 60*0.3= 18>10

2) n(1-p) = 60*(1-0.3)= 42>10

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})

The mean would be given by:

\mu_{\hat p}=0.3

And the deviation is given by:

\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592

6 0
3 years ago
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