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sesenic [268]
3 years ago
14

PLEASE ANSWER FAST!! Find the 29th term of this sequence:-121,-108,-95,-82...

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

The 29th term is

<h2>243</h2>

Step-by-step explanation:

The above sequence is an arithmetic sequence

For an nth term in an arithmetic sequence

U(n) = a + ( n - 1)d

where n is the number of terms

a is the first term

d is the common difference

From the question

a = - 121

d = -108 -- 121 = - 108 + 121 = 13

Since we are finding the 29th term

n = 29

The 29th term of the sequence is

U(29) = - 121 + ( 29 - 1) 13

= -121 + 28(13)

= -121 + 364

The final answer is

<h2>243</h2>

Hope this helps you

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3^-2 expanded form
Zanzabum

3^(-2) = 1/(3^2) = 1/(3*3) = 1/9

The rule used here is x^(-y) = 1/(x^y) to make the exponent positive.

3^2 turns into 3*3 because the exponent 2 tells us how many copies of the base '3' to multiply out.

5 0
3 years ago
Which of the following is the product of the rational expression shown below
wolverine [178]

Option C: \frac{x^{2}-9}{x^{2}-4} is the product of the rational expression.

Explanation:

The given rational expression is \frac{x+3}{x+2} \cdot \frac{x-3}{x-2}

We need to determine the product of the rational expression.

<u>Product of the rational expression:</u>

Let us multiply the rational expression to determine the product of the rational expression.

Thus, we have;

\frac{(x+3)(x-3)}{(x+2)(x-2)}

Let us use the identity (a+b)(a-b)=a^2-b^2 in the above expression.

Thus, we get;

\frac{x^{2} -3^2}{x^{2} -2^2}

Simplifying the terms, we get;

\frac{x^{2}-9}{x^{2}-4}

Thus, the product of the rational expression is \frac{x^{2}-9}{x^{2}-4}

Hence, Option C is the correct answer.

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Can someone please help me with # 2 #13 thanks show work how it's done, please
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Problem 13

10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get

10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q

so we get the original expression again. Here 10 is the GCF of the two terms.

--------------------------------------------------------------

Plug p = 1 and q = 2 into the factored form

10*(p+q) = 10*(1+2) = 10*(3) = 30

As a check, let's plug those p,q values into the original expression

10*p+10*q = 10*1+10*2 = 10+20 = 30

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