Question

9)

Answer 1

Answer:

$21 x^2 +75 x+36 =0$

Step-by-step explanation:

Let us assume that the negative integer is  -x

Now we have

Seventy - five times a negative integer = $75 (-x ) = -75 x$

Seventy - five times a negative integer minus 36 = $-75x - 36$

Square of negative integer = $(-x)^2 = x^2$

21 times the square of negative integer = $21 x^2$

Now it is given that

Seventy - five times a negative integer minus 36  is equal to 21 times the square of negative integer

So we have

$-75x -36 = 21 x^2$

We can also try to write this in standard form by bring all the terms to one side

$-75x = 21 x^2 +36$  ( adding 36 to both sides)

$0 = 21 x^2 +75 x+ 36$  ( adding 75x to both sides )

$21 x^2 +75 x+36 =0$  ( Answer )

Answer 2

-75x - 36 = -21x²

-75x   Seventy-five times a negative integer
-36   Minus 36
=   Equals
-21x²   The square of the negative integer

Hope this helps!