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Sidana [21]
3 years ago
6

The senate in a certain state is compromised of 58 republicans, 39 democrats, and 3 independents. How many committees can be for

med if each committee must have 3Republicans and 2 ​Democrats?
Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0
Defining C(n,r) as the number of combinations (order does not count) to choose r objects from n, where C(n,r)=n!/(r!(n-r)!)
there are 
C(58,3) ways to choose 3 from 58 republicans, 
and
C(39,2) ways to choose 2 from 39 democrats.
So the committee has
(C(58,3)*(C(39,2)) variants, or
58!/(3!55!) * 39!/(2!37!)
=30856*741
=22864296

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