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makkiz [27]
3 years ago
12

Which reflection rule, if any, can be used to prove that rectangle A(-8, -3), B(-2, -3), C(-2, -6), D(-8, -6) and rectangle A'(8

, -3), B'(2, -3), C'(2, -6), D'(8, -6) are congruent?
A) (x, y) → (-x, y)
B) (x, y) → (x, -y)
C) (x, y) → (-x, -y)
D) The rectangles are not congruent.
Mathematics
1 answer:
Lady_Fox [76]3 years ago
3 0
<span>rectangle A(-8, -3), B(-2, -3), C(-2, -6), D(-8, -6)
and rectangle A'(8, -3), B'(2, -3), C'(2, -6), D'(8, -6)
</span>
x is opposite and y stayed the same

answer
<span>A) (x, y) → (-x, y) </span>
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A researcher read a 12-page article in 30 minutes. On
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The perpendicular bisectors of AABC intersect at point<br> G. Find the length of BG.<br> B
Paladinen [302]

Answer:

\overline{GB} = 9

Step-by-step explanation:

The given parameters are;

The point of intersection of the perpendicular bisectors of the sides \overline{BC}, \overline{BA}, and \overline{CA} intersect (meet) at point G

Let D represent the point of intersection of the perpendicular bisector from G to \overline{BC}, we have for ΔBGD and ΔCGD;

\overline{GD} ≅ \overline{GD} by reflexive property

∠GDB = ∠GDC = 90° given that \overline{GD} is the perpendicular bisector of \overline{BC}

Similarly, \overline{DB} ≅ \overline{DC}, also given that  \overline{GD} is the perpendicular bisector of \overline{BC}

Therefore;

ΔBGD ≅ ΔCGD by Side-Angle-Side (SAS) rule of congruency

\overline{GB} ≅ \overline{GC}   by Congruent Parts of Congruent Triangles are Congruent, (CPCTC)

\overline{GB} = \overline{GC} = 9 by definition of congruency

∴ \overline{GB} = 9.

4 0
3 years ago
The table shows values for functions f(x)and g(x)
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In the figure below, points D, E, and F are the midpoints of the sides of LABC,
attashe74 [19]

Answers:

  • DE = 39
  • AB = 68
  • BE = 34

=============================================================

Explanation:

BC = 78 is parallel to the midsegment DE.

This parallel midsegment is half as long as BC, so DE = BC/2 = 78/2 = 39

-------

DF = 34 doubles to AB = 2*DF = 2*34 = 68, since the midsegment is half as the parallel side, so we just think in reverse of that process.

-------

BE = 34 for two reasons

  • Quadrilateral EBFD is a parallelogram with opposite sides BE and DF that are congruent.
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--------

We don't use the info that AC = 48.

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3 years ago
What is 37/5 as a mixed number?
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7 2/5 is a mixed number for 37/5.
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3 years ago
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