Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
A is 1/2
B is 2
C is -2
Step-by-step explanation:
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Answer:
5
Step-by-step explanation:
(13^2 - 12^2) ÷ 5
(169 - 144) ÷ 5
25 ÷ 5
5
Answer:
The value of 4x-x + 5 when x + 3 is 14
Step-by-step explanation:
4(3)= 12 - 3= 9 + 5= 14
Answer:
1.33
Step-by-step explanation:
