What is the difference between the highest and lowest number?

Find the least common multiple of 8b^2 and 5n^3

muminat

Answer:

The lcm is; 40b^2n^3

Step-by-step explanation:

There are no common factors between the two expressions and as such the lcm will be found by obtaining the product of he two;

8b^2*5n^3 = 40b^2n^3

5 0

4 years ago

Read 2 more answers

Find the derivative g(x)=ln(2x^2+1)

lana [24]

Answer:

4x / (2x^2+1)

Step-by-step explanation:

g(x)=ln(2x^2+1)

Using u substitution

u= 2x^2 +1

du = 4x dx

g'(x) = d/du ( g(u) du)

We know that the derivative of ln(u) = 1/u since this is always positive

= 1/ u* du

Substituting x back into the equation

g'(x) = 1/(2x^2+1) * 4x

= 4x / (2x^2+1)

8 0

3 years ago

Emily has 3 yellow, 8 green, 5 red, and 14 blue ankle bracelets in a bag. If Emily randomly selects an ankle bracelet out of the

Nookie1986 [14]

The total number of bracelets she has are

3+8+5+14 = 30

so, my available choices are 8 from green and 14 from blue
so total = 22
so the answer is = 22/30 = 11/15

8 0

3 years ago

The area of a square in square feet is

Sedaia [141]

Answer:

Part 1) The expression for the perimeter is $P=4(25z-3)$ or $P=100z-12$

Part 2) The perimeter when z = 15 ft. is $P=1,488\ ft$

Step-by-step explanation:

Part 1)

we have

$625z^{2}-150z+9$

Find the roots of the quadratic equation

Equate the equation to zero

$625z^{2}-150z+9=0$

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$625z^{2}-150z=-9$

Factor the leading coefficient

$625(z^{2}-(150/625)z)=-9$

$625(z^{2}-(6/25)z)=-9$

Complete the square. Remember to balance the equation by adding the same constants to each side

$625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)$

$625(z^{2}-(6/25)z+(36/2,500))=0$

Rewrite as perfect squares

$625(z-6/50)^{2}=0$

$z=6/50=0.12$ -----> root with multiplicity 2

so

The area is equal to

$A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}$

The length side of the square is $b=(25z-3)$

therefore

The perimeter is equal to

$P=4b$

$P=4(25z-3)$

$P=100z-12$

Part 2) Find the perimeter when z = 15 ft.

we have

$P=100z-12$

substitute the value of z

$P=100(15)-12=1,488\ ft$

4 0

3 years ago

F(x)=1/4x^2+1/2x-35/4 how do I factor fractions?

Ivanshal [37]

let's multiply both sides by the LCD of all fractions, in this case is 4, just to do away with the denominators for a few seconds

$\bf f(x) = \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{4}}{4[f(x)]=4\left( \cfrac{1}{4}x^2+\cfrac{1}{2}x-\cfrac{35}{4} \right)} \\\\\\ 4f(x) = x^2+2x-35\implies 4f(x) = (x+7)(x-5) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill f(x) = \cfrac{1}{4}(x+7)(x-5)~\hfill$

5 0

4 years ago